50x^2-55x+9=0

Solution for 50x^2-55x+9=0 equation:

50x^2-55x+9=0

a = 50; b = -55; c = +9;
Δ = b2-4ac
Δ = -552-4·50·9
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-35}{2*50}=\frac{20}{100}
=1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+35}{2*50}=\frac{90}{100}
=9/10
$